Confused...

help in what? understanding? code not working?

if your'e getting a syntax error (because I copy-Pasted your code, on this line: printf("Array real_numbers can stroe %ld items.\n",(sizeof(real_numbers));

your'e missing a closing parentheses so at the end of the line it should look like this (sizeof(real_numbers)));

sizeof() doesn't need a parenthesis holding it, so you should just write: sizeof(real_numbers)); instead of: (sizeof(real_numbers)));

ohh ok, well I learned in college that a float normally has a size of 4 bytes (or 32 bits which is 8*4 bytes) so whats going on here is that since your array of floats goes up to 5 (real_numbers[5]), the you multiply 5*4 bytes (thats why in the first printf you get 20 bytes ), then what these guys are writing... you see that they're doing a division, so that division is between the 20 bytes that you just got from the first multiplication, divided by the size of a float which is 4 from what we just said...thats where you get the 5 which is the amount of items you cans store in that array.

Hope it helps... basically what you are doing is simplifying a fraction (5*4)/4 = 5 cheers ;)

...and you spelt 'store' wrong ;o)

Thank you guys for your replies!! I Andres: I guess I need help with the concept. In the example in the video, the instructor (if forget his name right now) found the length by dividing the variable named by the float by the float itself: printf("Array real_numbers can store %ld items", sizeof(real_numbers)/sizeof(float));

i dont know if the question is asking for that or something else.

Your code: printf("Array real_numbers can stroe %ld items.\n",(sizeof(real_numbers));

The code you quote the instructor as using: printf("Array real_numbers can store %ld items", sizeof(real_numbers)/sizeof(float));

So you get that you made a typo on 'store' and missed a 'divided by' bit?

Do you want me to run through the concept (why your doing the device bit)?