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Start your free trialBrandon Evans
8,154 PointsConfused with this solution
Hello!
I was able to solve this challenge, however I am confused why I am returned a tuple when I call this method, instead of the actual product
I expect to see in console.
This is my code:
def multiply(*args):
product = 1
for arg in args:
product *= arg
return product
numbers = 1, 2, 3, 4, 5, 6
print(multiply(numbers))
When I run this in console, the interpreter returns: (1, 2, 3, 4, 5, 6)
Should I not expect to see a single integer (the product) returned in the console? Or am I misunderstanding something?
Thanks for the help! :)
1 Answer
Steven Parker
231,269 PointsThe packing operator (*) is causing the tuple "number" to be handled as a single item. It would do what you expect if you passed a number of individual arguments (such as "multiply(1, 2, 3, 4, 5, 6)
"). But when you pass a tuple in, you get the same tuple out.
But to make the function work on an iterable (like "number"), you'd want to remove the "splat": ("def multiply(args):
").
Brandon Evans
8,154 PointsBrandon Evans
8,154 PointsOOO! That makes perfect sense! :) I was oblivious to the fact the point of this challenge was to pass in multiple arguments lol. Duh. Perfect -- thanks so much for your explanation!