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Ronald Tse
5,798 PointsConfusing with pack and unpack
it keeps saying "format() argument after ** must be a mapping, not list"
What does it mean?
# Example:
values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
# ["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]
template = "Hi, I'm {name} and I love to eat {food}!"
def string_factory(values):
result_list = []
for value in values:
result_list.append(template.format(**values))
return result_list
2 Answers

Torsten Lundahl
2,570 PointsYou are formatting the string using 'values' instead of 'value'. 'values' is refering to the list, and 'value' is refering to the dict inside of that list. In other words your code is trying to unpack a list, when it is expecting to unpack a dictionary. Change 'values' to 'value' inside of format() and your code should work fine!

markmneimneh
14,132 PointsHello
Try this and see if it will point you into the right direction
values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
# ["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]
template = "Hi, I'm {} and I love to eat {}!"
def string_factory(values):
result_list = []
for dict in values:
result_list.append(template.format(dict['name'], dict['food']))
return result_list
print(string_factory(values))
if this answers your question, please mark question as answered.