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JavaScript Introduction to Programming Control Structures Quiz

Luke Nicholls
Luke Nicholls
4,536 Points
Posted by Luke Nicholls
Luke Nicholls
4,536 Points

Control Structures - Fizz Buzz Extra Credit

I'm not sure if this is the right place to ask my question but I would like to know what is the correct result for the Fizz Buzz challenge. I can do it for either 3 or five resulting in the right word replacement but i'm stuck on trying to do it for both at the same time.

Thanks in advance

3 Answers

Jason Anello
Jason Anello
Courses Plus Student 94,610 Points

Hi Luke,

You can use the logical AND operator &&

if (number % 3 == 0 && number % 5 == 0) { This will check that it's evenly divisible by both 3 AND 5

Or a more efficient way would be to realize that if a number is evenly divisible by both 3 and 5 then it must be evenly divisible by 15

if (number % 15 == 0) {

Whichever one you decide, it must be before the separate mod 3 and mod 5 checks.

Luke Nicholls
Luke Nicholls
4,536 Points
Luke Nicholls
Luke Nicholls
4,536 Points

Thanks Jason,

I did work it out with the following code but your way is definitely handy to know for the future.

Cheers

for (var i=100; i; i=i-1) {

var a = (i % 3);

var b = (i % 5);

if (a) {
    var x = false;
}

else {
    var x = true;
}

if (b) {
    var y = false;
}

else {
    var y = true;
}

if (x * y) {
    console.log("fizzbuzz");
}

else if (x) {
    console.log("fizz");
}

else if (y) {
    console.log("buzz");
}

else {
    console.log(i);
}

}

Michael Guren
Michael Guren
5,195 Points
Michael Guren
Michael Guren
5,195 Points

Here was my attempt:

counter = 1;
while(counter < 101){
    if (counter % 15 == 0) {
        console.log("fizzbuzz");
    }else if(counter % 3 == 0){
        console.log("fizz");
    }else if(counter % 5 == 0){
        console.log("buzz");
    }else{
        console.log(counter);
    }
    counter = counter + 1
}