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# Control Structures - Fizz Buzz Extra Credit

I'm not sure if this is the right place to ask my question but I would like to know what is the correct result for the Fizz Buzz challenge. I can do it for either 3 or five resulting in the right word replacement but i'm stuck on trying to do it for both at the same time.

Hi Luke,

You can use the logical AND operator `&&`

`if (number % 3 == 0 && number % 5 == 0) {` This will check that it's evenly divisible by both 3 AND 5

Or a more efficient way would be to realize that if a number is evenly divisible by both 3 and 5 then it must be evenly divisible by 15

`if (number % 15 == 0) {`

Whichever one you decide, it must be before the separate mod 3 and mod 5 checks.

Thanks Jason,

I did work it out with the following code but your way is definitely handy to know for the future.

Cheers

for (var i=100; i; i=i-1) {

```var a = (i % 3);

var b = (i % 5);

if (a) {
var x = false;
}

else {
var x = true;
}

if (b) {
var y = false;
}

else {
var y = true;
}

if (x * y) {
console.log("fizzbuzz");
}

else if (x) {
console.log("fizz");
}

else if (y) {
console.log("buzz");
}

else {
console.log(i);
}
```

}

Here was my attempt:

```counter = 1;
while(counter < 101){
if (counter % 15 == 0) {
console.log("fizzbuzz");
}else if(counter % 3 == 0){
console.log("fizz");
}else if(counter % 5 == 0){
console.log("buzz");
}else{
console.log(counter);
}
counter = counter + 1
}
```