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Python

Posted by srikanth soma
srikanth soma
1,572 Points

Convert string to dictionary?

Alright, this one might be a bit challenging but you've been doing great so far, so I'm sure you can manage it. I need you to make a function named word_count. It should accept a single argument which will be a string. The function needs to return a dictionary. The keys in the dictionary will be each of the words in the string, lowercased. The values will be how many times that particular word appears in the string. Check the comments below for an example.

For the following above task this is what I'm thinking I don't know whether I'm in right direction or not.

  • First created new function with one argument
  • convert that argument to lower case
  • created new dictionary
  • Iteration through argument and split it by space I used string.split(" ") I suppose this should split by space but for some reason it splits by each letter in word.
  • and I thought once I split that by space then add that to dict that I created(dict = {}) and I've no Idea how to count those words occurence.

Can someone help me whether my thought process is atleast in right direction or how bad I'm thinking this?

def word_count(arg):
    string = arg.lower()
    dict = {}
    for words in string:
        word_split_by_space = words.split(' ')
        print(word_split_by_space)

word_count("Hello World")
rainmaker
rainmaker
14,690 Points

Try not to use python keywords as variable names.. i.e: you are using string and dict which are python keywords you never added the words from your for loop to the dictionary nor did you count the amount of times the word appears in the string. 

def word_count(arg):
    lower_string = arg.lower() 
    word_list = list(lower_string.split())
    string_dict = dict()
    for word in word_list:
        string_dict[word] = word_list.count(word)
    return string_dict