Copy-paste your code in between the comments shown below. Your solution is going inside a function I created. Don't worr

Hey Akbar Khatibi,

Great job on solving FizzBuzz! You just need to format this code according to the challenge to get it to pass. First, we need to remove the for loop. The challenge is providing you with a function that takes a single parameter, called n, of type integer. This allows you to pass any valid integer value into the function call, in order to solve for whether or not n fits the "Fizz", "Buzz", or "FizzBuzz" requirements. Therefore, the range provided by the loop is not needed. Second, you just have to move the return statement for the function inside of the function body.

Take a look at my code below:

func fizzBuzz(n: Int) -> String {
  // Enter your code between the two comment markers
    if (n % 3 == 0) && (n % 5 == 0){
        return "FizzBuzz"
    } else if (n % 3 == 0) {
        return "Fizz"
    } else if (n % 5 == 0) {
      return "Buzz"
    }

  // End code
  return "\(n)"
}

Good Luck!