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Start your free trialMarina Shumeyko
5,647 PointsCould we use +prompt() instead of parseInt() ?
Just because it is shorter ? What is the most common practice ?
var firstNumber = +prompt('Enter your first number');
var secondNumber = +prompt('Enter your second number');
var randomNumber = Math.floor(Math.random() * (secondNumber - firstNumber + 1) + firstNumber);
document.write(randomNumber + ' is a number between ' + firstNumber + ' and ' + secondNumber);
Marina Shumeyko
5,647 PointsYes Savannah. That is more simple way to convert string to the number. But you are right it would be just a number, but not always an integer?
To put before the expression unary plus "+" Just try some examples in console as:
var a = +"123"; // 123:
var a = Number("123"); // 123,
alert( +" \n 123 \n \n" ); // 123
alert( +true ); // 1
alert( +false ); // 0
Type Result
undefined NaN
null 0
true / false 1 / 0
console.log(+value); // number
3 Answers
Savannah Lynn
13,662 PointsI'm guessing that is the limitation with using + only. If you really need it to be specifically an integer, parseInt is probably still the safest. Thanks for teaching me that trick though!
Raphaël Seguin
Full Stack JavaScript Techdegree Graduate 29,228 PointsHi, I didn't know that trick either. Thank you. I found that one alter, which could interest you :
~~98.2392847; // 98
~~0; // 0
~~0.12134; // 0
~~1.0000002 // 1
It always returns the entire part !
Marina Shumeyko
5,647 PointsThanks for the answer to my question @Savannah
Savannah Lynn
13,662 PointsSavannah Lynn
13,662 PointsHi Marina,
Where did you learn about +prompt()? I can't find any documentation on it. Does the + before it work like parseInt() in that it converts it to an integer?