Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Collections (2016, retired 2019) Sets Set Math

Dmitriy Ignatiev
PLUS
Dmitriy Ignatiev
Courses Plus Student 6,236 Points

covers_all

Hi there. Couldn't solve challenge 2/2

Please help me understand how to solve.

sets.py
COURSES = {
    "Python Basics": {"Python", "functions", "variables",
                      "booleans", "integers", "floats",
                      "arrays", "strings", "exceptions",
                      "conditions", "input", "loops"},
    "Java Basics": {"Java", "strings", "variables",
                    "input", "exceptions", "integers",
                    "booleans", "loops"},
    "PHP Basics": {"PHP", "variables", "conditions",
                   "integers", "floats", "strings",
                   "booleans", "HTML"},
    "Ruby Basics": {"Ruby", "strings", "floats",
                    "integers", "conditions",
                    "functions", "input"}
}

def covers (parametr):
    new_list = []
    for i in COURSES:
        if COURSES[i] & parametr :
            new_list.append(i)
    return (new_list)

1 Answer

Dictionaries don't have indexes Try something that runs through the key value pairs instead.

 for key, value in COURSES.items():
        if set(parametr) & set(value):
            solution.append(key)