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Start your free trialAdam Fields
4,487 PointsCreate a for loop that logs the numbers 4 to 156 to the console. To log a value to the console use the console.log( )
what am I doing wrong?
var num;
for(var i=4; i<=156;+=1)
num+=1 + i;
console.log(num);
}
2 Answers
Steven Parker
231,269 PointsI don't understand those calculations with "num", but you really don't need "num" at all. Just log the loop variable "i".
But you also have a syntax error in the final "for" loop clause: instead of "+=1
" you need "i+=1
" (to increment "i").
I'll bet you can get it now without an explicit code spoiler.
Kieran Barker
15,028 PointsHey Adam,
You're close! This is the correct code for this challenge:
for ( var i = 4; i <= 156; i++ ) {
console.log( i );
}
What this code is doing is as follows:
- Initializing a counter variable with the value
4
. - Before each loop iteration, the JavaScript interpreter checks to see if the current value of
i
(which will be4
the first time around) is less than156
. If it is, then the loop will run. - The JavaScript interpreter executes everything inside the code block β thatβs everything inside the curly braces. In this case, the current value of
i
is logged to the console each time the loop runs. - At the end of the loop, the counter variable --
i
-- is updated by1
. So the next time around it will be5
. The loop will stop running when the condition is no longer true, i.e. wheni
is no longer less than156
.
A quick note...
- I used
++
to increcementi
, buti += 1
will do the same thing.
Please let me know if you have any questions!
~ Kieran
Adam Fields
4,487 PointsAdam Fields
4,487 Pointsthank you steven I figured it out thank you .