Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
Mark Wisdom Reeves
Full Stack JavaScript Techdegree Graduate 18,275 PointsCreate a for loop that logs the numbers 4 to 156 to the console. To log a value to the console use the console.log( ) me
for ( var i = 4; i < 160; i += 1 ) { console.log(i); }
for ( var i = 4; i < 160; i += 1 ) {
console.log(i);
}
3 Answers
Barbara Smok
Front End Web Development Techdegree Graduate 14,687 PointsLooks like you just need to add an = to the for loop condition so it's i <= 156. By not including the = it will not log the number 156 to the console because it will stop looping at number 155 (it stops once i is no longer less than 156, where the last number logged to the console is 155). Including the = allows the loop to run one more time and log 156 to the console.
Jamie Reardon
Treehouse Project ReviewerThe challenge wants you to log the numbers up to 156, not 160, change your condition.
Mark Wisdom Reeves
Full Stack JavaScript Techdegree Graduate 18,275 PointsThanks very much. That was my mistake
Jamie Reardon
Treehouse Project ReviewerVery welcome
Barbara Smok
Front End Web Development Techdegree Graduate 14,687 PointsI'm writing this answer but I'm getting an error message: Bummer: You need to log out EVERY number from 4 to 156 to the console. Your loop calls the console.log() method 152 times.
for ( var i = 4; i < 156; i += 1 ) { console.log(i); }
If anyone can help me out please!