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Adam Raitano
5,387 PointsCreate a function named combo...
I'm getting the 'bummer' message here. It tells me that I'm effectively correct except for I have [(0, 'T'), (1, 'r'), (2, 'e')... and it's expecting [(1, 'T'), (2, 'r'), (3, 'e')...
What could I possibly be doing wrong here?
# combo(['swallow', 'snake', 'parrot'], 'abc')
# Output:
# [('swallow', 'a'), ('snake', 'b'), ('parrot', 'c')]
# If you use list.append(), you'll want to pass it a tuple of new values.
# Using enumerate() here can save you a variable or two.
def combo(it1, it2):
silt = []
for item1, item2 in enumerate(it2):
new_silt = (item1, item2)
silt.append(new_silt)
return silt
2 Answers
Anish Walawalkar
8,534 PointsRemember that list indices always start at 0
# combo(['swallow', 'snake', 'parrot'], 'abc')
# Output:
# [('swallow', 'a'), ('snake', 'b'), ('parrot', 'c')]
# If you use list.append(), you'll want to pass it a tuple of new values.
# Using enumerate() here can save you a variable or two.
def combo(it1, it2):
silt = []
for item1, item2 in enumerate(it2):
new_silt = (item1+1, item2)
silt.append(new_silt)
return silt
doing the following should fix your error
another way of doing this would be to use dic(zip(list1, list2)):
item1 = list(range(1, len(item2)+1)) # because you want to start at index 1
dictionary = dict(zip(item1, item2))
return dictionary
That should do it
Adam Raitano
5,387 PointsThanks for your response! I think I kind of misunderstood what I was supposed to do. I did, however, figure out the right way. Hooray!