John MclanePro Student 3,099 Points
create a function named combo function: Do you have a different solution? Here is mine!
I came up with a viable solution that passed. However, I wanted to get your take on what worked for you all? I don't know if was supposed to use the *args. I'd love to know how you all tackled the challenge. Thanks in advance!
# example I used to test was # first_iterable = 'tre' # second_iterable = [1,2,3] # My logic was that I wanted to split the given iterables into a list format # then take each element of first_iterable list and second_iterable list and create a tuple def combo(first_iterable,second_iterable): list_of_things =  first_iterable_list = list(first_iterable) second_iterable_list = list(second_iterable) index = 0 for value in first_iterable_list: first_iterable_value = first_iterable_list[index] second_iterable_value = second_iterable_list[index] tuple_value = (first_iterable_value, second_iterable_value) list_of_things.append(tuple_value) index += 1 return list_of_things
Steven Parker203,990 Points
Good job! You've implemented the classic strategy.
Optionally, there's a few things you can do to make the code more compact:
- the iterables don't need to be converted into lists
- the loop could use "index" directly with a range based on the length of either argument
- the indexed items can be made into a tuple directly (without intermediate variables)
Also, in case you didn't know, this function implements essentially the same thing as the built-in function named "zip". But of course, the challenge doesn't allow you to use that in your solution!