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Start your free trialRakesh Bharadwaj
1,376 PointsCreate a function named combo that takes two ordered iterables. These could be tuples, lists, strings, whatever.
Create a function named combo that takes two ordered iterables. These could be tuples, lists, strings, whatever.
I could get the exact output as required
# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
def combo(*args):
b =list(args)
#print(b)
d = list(b[0])
c = list(b[1])
e = ()
f = ()
i = 0
while i <= len(b):
e = (d[i],c[i])
f += (e,)
i += 1
return list(f)
3 Answers
Boris Ivan Barreto
6,838 PointsI managed to solve the task this way
def combo(*arg):
my_result = []
for index, val in enumerate(arg[0]):
my_result.append((val, arg[1][index]))
return my_result
Viktor Léhner
12,771 PointsVery nice and simple solution!
Steven Parker
231,269 PointsBoris's solution is clever, but rather unconventional and complicated. Much more concise solutions are possible, and it's also not necessary to use "enumerate" or the unpacking operator. For example:
def combo(a, b):
return [(a[i], b[i]) for i in range(len(a))]
Bruno Aldo Lunardi
15,795 PointsBruno Aldo Lunardi
15,795 PointsI had quite a tough time thinking about a shorter solution for this one and you provided such an elegant and simple solution here, thanks !!
Christian A. Castro
30,501 PointsChristian A. Castro
30,501 PointsBoris Ivan Barreto beautiful!! thanks for the hint