Create a function named find_words that takes a count and a string. Return a list of all of the words of length "count"

I'd just like to say that, after spending the time I did on solving this particular challenge, I think it detracted from the flow of my learning, and while it was certainly tricky, and perhaps good practice for string manipulation, I'm not sure that it was quite as helpful towards the goal learning regex. If the goal was to elucidate the need for concatenation of variables within regex functions, I think a lesser initial challenge might have sufficed. Just saying. ;)

def find_words(my_string, my_count): #put all the words in a list
my_list = list(my_string.split())

#the string that will hold the output my_output_string = []

for each_string in my_list: if len(each_string) == my_count: my_output_string.append(each_string)

return my_output_string

Bummer! Didn't get the right output. Output was ['123456,', 'Treehouse,', 'student,', 'learn,', 'Kenneth,', 'Python,', 'regex,', 'match,', 'Ryan,']. Length was 6.

import re def find_words(number, words): return re.findall(r'\w+,', words)

should I be using {}.format and to substitute at this point?

import re
def find_words(int, str): 
  return re.findall(r'\w{}'.format(int+str))

... this was close, but not passing. How else can I add them together?

Can't figure out why it won't take my {count, }?

def find_words(count, string):
    return re.findall(r'\w{count,}', string) 

Thanks Kenneth - I'm still gettting an error and I know it will be some small detail I've overlooked.

def find_words(count, string):
  return re.findall(count * r'\w', string)

It was similarr to the code I posted above, but I gave the count * something to count on from {1,}

As best as I can tell, the following is what several hinters seem to be eluding to, however it does not appear to solve the challenge, - where am I going wrong here?:

import re def find_words(count, string): count = str(count) return re.findall(r'\w{'+ count + ', }', string)

count = str(count) is not needed.

You want to be returning re.findall( inside these you need to be multiplying '\w' against the string) remember to specify 1 or more places use {1, }.

I've solved it, but the code feels a little messy. Should I post the solution here for you to comment on? I'd rather not just be handing the answer out.