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Start your free trialAl Craig
22,220 PointsCreate a function named most_courses that takes our good ol' teacher dictionary.
Struggling with this next step... Where am I going wrong?
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(dict_teachers):
return len(dict_teachers)
def num_courses(dict_teachers):
courses = []
for course in dict_teachers.values():
courses += course
courses = set(courses)
return len(courses)
def courses(dict_teachers):
courses = []
for course in dict_teachers.values():
courses += course
return set(courses)
def most_courses(dict_teachers):
max_length = 0
longest = ''
for key, value in dict_teachers.items():
if max_length = 0:
max_length = len(value)
longest = key
elif len(value) > max_length:
max_length = len(value)
longest = key
return longest
4 Answers
Al Craig
22,220 PointsThe most_courses function needs to return the key (teacher) with the greatest len(value) (the most courses).
Al Craig
22,220 PointsThis still doesn't pass. :(
def most_courses(dict_teachers):
max_length = 0
for key, value in dict_teachers.items():
if max_length == 0:
max_length = len(value)
longest = key
elif len(value) > max_length:
max_length = len(value)
longest = key
return longest
Dave StSomeWhere
19,870 PointsPasses challenge 4 of 5 for me, Did you restart the challenge and/or your browser?
Al Craig
22,220 PointsPasses now. I must have had something weird hidden in the code. Thanks.
Dave StSomeWhere
19,870 PointsDave StSomeWhere
19,870 PointsLooks like you are using an assignment operator in 1 spot where you really want to evaluate equality.