Create a function named string_factory that accepts a list of dictionaries and a string. Return a new list using .format

Question

Create a function named string_factory that accepts a list of dictionaries and a string. Return a new list build by using .format() on the string, filled in by each of the dictionaries in the list.

dicts = [
    {'name': 'Michelangelo',
     'food': 'PIZZA'},
    {'name': 'Garfield',
     'food': 'lasanga'},
    {'name': 'Walter',
     'food': 'pancakes'},
    {'name': 'Galactus',
     'food': 'worlds'}
]

string = "Hi, I'm {name} and I love to eat {food}!"

# create the function string_factory
# extract each dictionary from the list - dicts[0] = {'name': 'Michelangelo', 'food': 'PIZZA'}
# fill the string using "**" trick
# put each string into the new list

new_list = []

def string_factory():
# I could run for in loop, but I don't know how to do string.format one each member of the list (dicts[0]) 
# for each_dict in dicts:
    new_dicts1 = dicts[0]
    new_dicts2 = dicts[1]
    new_dicts3 = dicts[2]
    new_dicts4 = dicts[3]
# how to run string.format on each member of dicts list ???   
    new_string1 = string.format(**new_dicts1)
    new_string2 = string.format(**new_dicts2)
    new_string3 = string.format(**new_dicts2)
    new_string4 = string.format(**new_dicts2)
# is there a way to append / add all new strings at the same time ?    
    new_list.append(new_string1)
    new_list.append(new_string2)
    new_list.append(new_string3)
    new_list.append(new_string4)

    return new_list

[MOD: added ```python markdown formatting -cf]

Answer 1 · 2015-12-08T23:16:39Z

December 8, 2015 11:16pm

Your code is very close!

add missing parameters for dicts and the string
remove inner loop. You can expand directly from the dict:

new_list = []

def string_factory(dicts, string):  # <-- Added parameters

    for each_dict in dicts:
        # remove inner loop
        # for key in each_dict:    # <-- I am struggling with running second for in loop for each dictionary in the list
            new_string = string.format(**each_dict)  # <-- replace 'key' with 'each_dict'
            new_list.append(new_string)

    return new_list

This code will pass. Indentation should be cleaned up after edits.

Answer 2 · 2015-12-07T11:57:48Z

December 7, 2015 11:57am

Basically it could look like something like this... I am struggling with running second for in loop for each dictionary in the list. Please help.

new_list = []

def string_factory():

    for each_dict in dicts:
        for key in each_dict:    # <-- I am struggling with running second for in loop for each dictionary in the list
            new_string = string.format(**key)
            new_list.append(new_string)

    return new_list

[MOD: added ```python markdown formatting -cf]

Answer 3 · 2015-12-09T10:26:36Z

December 9, 2015 10:26am

Chris, thanks again!

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frankgusto

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Create a function named string_factory that accepts a list of dictionaries and a string. Return a new list using .format

Ryan Flyod

Ryan Flyod

3 Answers

Chris Freeman

Chris Freeman

Ryan Flyod

Ryan Flyod

Chris Freeman

Chris Freeman

frankgusto

frankgusto

frankgusto

frankgusto