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frankgusto
4,091 PointsCreate a function named word_count() that takes a string. Return a dictionary with each word in the string as the key an
Guys, need help with the code. Not sure what I am doing wrong.
my_string = "I am here you are there I you you"
def word_count(my_string):
string_lowercase = my_string.lower()
string_split = string_lowercase.split()
my_dict = {}
for word in string_split:
if word in string_split:
my_dict[word] = 1
else:
my_dict[word] += 1
return my_dict
[MOD: added ```python formatting -cf]
3 Answers
Chris Freeman
Treehouse Moderator 68,423 PointsYour code is very close! In detecting if the word has been seen you need to fixed to things: search the keys of my_dict instead of string_split and reverse the conditions so that you initialize the count to 1 if not in string_split:
def word_count(my_string):
string_lowercase = my_string.lower()
string_split = string_lowercase.split()
my_dict = {}
for word in string_split:
if word not in my_dict: # <-- corrected this line.
my_dict[word] = 1
else:
my_dict[word] += 1
return my_dict
Evan Demaris
64,262 PointsYou could simplify it a bit with:
def word_count(my_string):
my_dict = {}
for word in my_string.lower().split():
if word in my_dict:
my_dict[word] += 1
else:
my_dict[word] = 1
return my_dict
frankgusto
4,091 PointsChris, thanks for your help.