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# Create a function that calculates the difference between dates and checks if it is bigger than a number

Hi, I'm having troubles solving this one. I cannot get how to compute the difference between dates. I suspect there is an easier way that the one I try below. Your help will be greatly appreciated.

birthdays.py
```import datetime

birthdays = [
datetime.datetime(2012, 4, 29),
datetime.datetime(2006, 8, 9),
datetime.datetime(1978, 5, 16),
datetime.datetime(1981, 8, 15),
datetime.datetime(2001, 7, 4),
datetime.datetime(1999, 12, 30)
]

is over_13(date):
today = datetime.datetime.today()
diff = today - date
return round(diff.seconds/86400) >= 4745
```

MOD

Hi Jose, two issues with your current code: the function definition syntax, and the use of the timedelta object `diff`

The proper function should be defined using the keyword `def` and no spaces in the function name:

```def is_under_13(date):
```

Subtracting two`daatetime` objects results in a `timedelta` object. In your code, you've call it `diff`. A `timedelta` object has these properties (from `help(datetime.timedelta`):

``` |  days
|      Number of days.
|
|  microseconds
|      Number of microseconds (>= 0 and less than 1 second).
|
|  seconds
|      Number of seconds (>= 0 and less than 1 day).
```

Note that the `seconds` attribute contains only the partial seconds of less than 1 day. You need to use the `days` attribute. Add this to your code:

```def is_over_13(date):
#today = datetime.datetime.today() #<-- not needed defined as global
diff = today - date
return diff.days >= 4745
```