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JavaScript

Jordan Hammond
Jordan Hammond
2,278 Points
Posted by Jordan Hammond
Jordan Hammond
2,278 Points

Create a function that takes 3 arguments, a, b, and c. If a is an even number have the function return the string "even"

Can someone help me understand why this would return as "Uncaught TypeError: undefined is not a function "? It's from the extra credit question. It did display "odd" though so that's good.

var practice = function(a, b, c){
    if (a%2==0){
        console.log("even")
    } else {
        console.log("odd")
    }
}

var x = practice(1, 2, 3)

x()

Thanks!

2 Answers

Lush Sleutsky
Lush Sleutsky
14,044 Points
Lush Sleutsky
Lush Sleutsky
14,044 Points

Your code runs fine when I run it, with the exception of

x()

at the end there. That is not needed.

And also, you did take some extra steps... You don't need

var x = practice(1, 2, 3)

as you could just have called the function like so:

practice(1, 2, 3)

Also, try to change this line to:

if (a%2 === 0)

Three equals might make it work in whatever you're testing it, but I ran it the just the way you had it in the Chrome console, and the results were fine...

Jeff Busch
Jeff Busch
19,287 Points
Jeff Busch
Jeff Busch
19,287 Points

Hi Jordan,

The function practice() doesn't return anything, it just outputs to the console. So essentially the statement, var x = practice(1, 2, 3) means x equals nothing returned.

Jeff