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PHP PHP Basics (Retired) PHP Data & Structure PHP Variables

Create a PHP Code Block with a Variable called "name" inside of that block and set it equal to "Mike".

This is the challenge

My solution was

$name="Mike";

<?php echo $name ?>

It returns an error saying. Make sure you call; your variable $name

index.php
$name="Mike";

<?php echo $name ?>

3 Answers

John Lukacs
John Lukacs
26,210 Points

I don't think you need a $ sign when calling it. I mean take out the second dollar sign.

Thanks for the quick reply.

The problem was, the challenge needed variable to be created inside PHP code instead. and Call it. What I did was I created it outside and called it inside the php tags

That solved the problem

John Lukacs
John Lukacs
26,210 Points

yeah its been a while since I touched php looking at it now

Matthew Calbeck
Matthew Calbeck
5,094 Points

I think you need to assign your $name variable inside of the PHP tags. Also, you would need to end your echo statement with a semi-colon.

You right Matthew.

Thanks