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JEFFERSON DCRUZ
Courses Plus Student 7,772 PointsCreate a PHP Code Block with a Variable called "name" inside of that block and set it equal to "Mike".
This is the challenge
My solution was
$name="Mike";
<?php echo $name ?>
It returns an error saying. Make sure you call; your variable $name
$name="Mike";
<?php echo $name ?>
3 Answers
John Lukacs
26,806 PointsI don't think you need a $ sign when calling it. I mean take out the second dollar sign.
John Lukacs
26,806 Pointsyeah its been a while since I touched php looking at it now
Matthew Calbeck
5,094 PointsI think you need to assign your $name variable inside of the PHP tags. Also, you would need to end your echo statement with a semi-colon.
JEFFERSON DCRUZ
Courses Plus Student 7,772 PointsYou right Matthew.
Thanks
JEFFERSON DCRUZ
Courses Plus Student 7,772 PointsJEFFERSON DCRUZ
Courses Plus Student 7,772 PointsThanks for the quick reply.
The problem was, the challenge needed variable to be created inside PHP code instead. and Call it. What I did was I created it outside and called it inside the php tags
That solved the problem