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Android Build a Simple Android App with Kotlin Basic Android Programming Using the Random Class

Posted by Daniel Moravec
Daniel Moravec
236 Points

Create a String variable called randomNumber, and set it equal to a random Integer between 0 and 9.

I was learning Android development with Kotlin at Treehouse and there was this question: Create a String variable called randomNumber, and set it equal to a random Integer between 0 and 9. I would write it as:

import java.util.Random

val randomNumber = Random(10)

But this does not work and it keeps telling me: "randomNumber should be a String". Can anybody please help me solve this problem?

RandomTest.kt 
import java.util.Random


val randomNumber = Random()

3 Answers

Sai Krishna Katkam
PLUS
Sai Krishna Katkam
Courses Plus Student 1,946 Points
Sai Krishna Katkam
Sai Krishna Katkam
Courses Plus Student 1,946 Points

Random is just a class.

randomNumber is an variable of String type.

val randomNumber: String = Random()

nextInt() is a method/function in the Random class for generating a random number between N numbers. (here N=10)

val randomNumber: String = Random().nextInt(10)

toString() is a method/function in the Object class for returning a String representation of the object. (Since nextInt() would return an integer, but whereas randomNumber is a String variable, we use toString() method.)

val randomNumber: String = Random().nextInt(10).toString()
Daniel Moravec
Daniel Moravec
236 Points

Thanks a lot, now I get it! :)

janet178
janet178
4,220 Points
janet178
janet178
4,220 Points

Thanks guys! I am watching the same tutorial. I was so close yet so far!

jose oswaldo guerrero valencia
jose oswaldo guerrero valencia
1,300 Points
jose oswaldo guerrero valencia
jose oswaldo guerrero valencia
1,300 Points

hi guys , i have this code , import java.util.Random

val randomNumber:String val randomGenerator: Random()

val randomNumber: randomGenerator.nextInt(10)

Im having trouble to do the exercise?