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Java Spring Basics Creating Controllers and Views Create a Controller to Handle HTTP Requests

Posted by Julya Savina
Julya Savina
1,929 Points

Creating my own method from example. Not sure how to make another method that works with localhost:8080/gif

I tried making another class file (gifController example) but anything I do just doesn't let build be executed (errors on bootRun.) Can I ask how somebody did this at the end of the lesson? I'm also specifically curious about how to get it to link to localhost:8080/gif

Thanks

1 Answer

Boban Talevski
Boban Talevski
24,793 Points
Boban Talevski
Boban Talevski
24,793 Points

Hi Julya.

You shouldn't be creating a new class for this, you just need to add another method in the same class. The method name can be anything you want, I chose listGifDetails, and the only additional change should be the value in the @RequestMapping annotation, so it should be @RequestMapping("/gif"), meaning we want this method to capture HTTP request to that particular URI /gif. For making sure it all works, just make it return another String message, I chose "Details of a particular GIF".

This is how my GifController class looks after adding that method:

package com.bobantalevski.giflib.controller;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.ResponseBody;

@Controller
public class GifController {

    @RequestMapping("/")
    @ResponseBody
    public String listGifs() {
        return "List of all the GIFs";
    }

    @RequestMapping("/gif")
    @ResponseBody
    public String listGifDetails() {
        return "Details of a particular GIF";
    }
}