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Start your free trialcarlos sulsona
10,378 Pointscreating UIIamgeview instances? i'm confused help please
In our Treehouse model struct below we have a property named friends. It is a dictionary that holds information about our friends including their profile pictures. In the ViewController class, using the key profilePicture, retrieve the image name as a string from the dictionary and assign it to a constant named profileImageName. I’ve already created an instance of the Treehouse struct and stored a reference to the friends library in a constant named friends for you to use.
Once you have the image name, create an instance of UIImage using the image name and store it in a constant called profilePicture.
import UIKit
class ViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
let friends = Treehouse().friends
//Add your code below
}
}
struct Treehouse {
let friends = [
"firstName": "Susan",
"lastName": "Olson",
"profilePicture": "susan_profile.png"
]
}
3 Answers
Chris Shaw
26,676 PointsHi Carlos,
The challenge itself want's you to create an UIImage
instance which is different from an UIImageView
which can contain many UIImage
instances, for this challenge you need to do the following:
- Assign the value for the key profilePicture in the
friends
dictionary to a constant calledprofileImageName
- Create a new instance of
UIImage
using thenamed
convenience constructor and theprofileImageName
constant we just set, we also need to assign ourUIImage
instance to another constant calledprofilePicture
The final result will look like the below.
let friends = Treehouse().friends
let profileImageName = friends["profilePicture"]
let profilePicture = UIImage(named: profileImageName)
Hope that helps.
Matthew Nos
4,982 PointsGood answer... addendum:
<code> let profileImageName = friends["profilePicture"] as String! </code>
carlos sulsona
10,378 PointsThanks :-)
Chris Shaw
26,676 PointsYou're welcome.
Frankz Kastner
4,188 PointsFrankz Kastner
4,188 Pointslet profileImageName = friends["profilePicture"] as String!