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Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.  # Curious about the interaction between the return statement and print

I realize the code doesn't work properly because of the list iteration and the way it manipulates it, but I noticed whenever I would return 'word', I would end up getting "whaaat" instead of "what", which should have been the incorrect answer. When I change the print statement to print(disemvowel(word)), it works fine.

Why doesn't calling the function then printing, result in "what"?

disemvowel.py
```def disemvowel(word):
i = 0
word_list = list(word)
while i < len(word_list):
if word_list[i] == "a":
del(word_list[i])
i += 1
word = "".join(word_list)
return word

word = "whaaat"
disemvowel(word)
print(word)
```

You need to assign the function to word in order to update word. Try the following:

```word = "whaaat"
word = disemvowel(word)
print(word)
```

It's scope issue, the word variable has declared as a global variable, so you have to override it word = "whaaat" word = disemvowel(word) print(word)

or you can use print the disemvowel function instead of return as the following

def disemvowel(word): i = 0 word_list = list(word) while i < len(word_list): if word_list[i] == "a": del(word_list[i]) i += 1 word = "".join(word_list) print(word)

word = "whaaat" disemvowel(word)