Curious about the interaction between the return statement and print

Question

I realize the code doesn't work properly because of the list iteration and the way it manipulates it, but I noticed whenever I would return 'word', I would end up getting "whaaat" instead of "what", which should have been the incorrect answer. When I change the print statement to print(disemvowel(word)), it works fine.
Why doesn't calling the function then printing, result in "what"?
```disemvowel.py
def disemvowel(word):
    i = 0
    wordlist = list(word)
    while i < len(wordlist):
        if wordlist[i] == "a":
            del(wordlist[i])
        i += 1
    word = "".join(word_list)
    return word
word = "whaaat"
disemvowel(word)
print(word)
```

KRIS NIKOLAISEN · Accepted Answer

You need to assign the function to word in order to update word. Try the following:
python
word = "whaaat"
word = disemvowel(word)
print(word)

MoatazBellah Ghobashy · Answer

It's scope issue, the word variable has declared as a global variable, so you have to override it
word = "whaaat"
word = disemvowel(word)
print(word)
or you can use print the disemvowel function instead of return as the following 
def disemvowel(word):
    i = 0
    wordlist = list(word)
    while i < len(wordlist):
        if wordlist[i] == "a":
            del(wordlist[i])
        i += 1
    word = "".join(word_list)
    print(word)
word = "whaaat"
disemvowel(word)

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Musashi Schroeder

Musashi Schroeder

Curious about the interaction between the return statement and print

2 Answers

KRIS NIKOLAISEN

KRIS NIKOLAISEN

Musashi Schroeder

Musashi Schroeder

MoatazBellah Ghobashy

MoatazBellah Ghobashy