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Python Functional Python Functional Workhorses attrgetter

Callum Anderson
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Callum Anderson
Data Analysis Techdegree Student 10,200 Points
Posted by Callum Anderson
.a{fill-rule:evenodd;}techdegree
Callum Anderson
Data Analysis Techdegree Student 10,200 Points

Curious of an alternate way of completing the challenge

I understand that with code challenges that its one way or no way from what it wants but really curious to see if this would work or why it doesn't. Code below.

Thanks

sorting.py 
import datetime
from operator import attrgetter

date_list = [
    datetime.datetime(2015, 4, 29, 10, 15, 39),
    datetime.datetime(2006, 8, 15, 14, 59, 2),
    datetime.datetime(1981, 5, 16, 2, 10, 42),
    datetime.datetime(2012, 8, 9, 14, 59, 2),
]

sorting_dates = sorted(date_list, key=attrgetter(datetime.strptime(date_list, %d)))
print(sorting_dates)

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,423 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,423 Points

Interesting approach. Perhaps you meant to use strftime which produce a str from a datetime object instead of strptime which produces a datetime object by parsing a string according to a format template. The argument to key must be a callable function that produces a comparable object ("a > b", etc.) so it can be applied to each item in the sorted container. Using strftime and a lambda function passes the challenge:

Also, challenge looking for sorted_dates not sorting_dates.

sorted_dates = sorted(date_list, key=lambda x: str(attrgetter(x.strftime("%d"))))

Post back if you have more questions. Good luck!!