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CSS CSS Basics (2014) Understanding Values and Units Styling the Intro Paragraph

Aaron Barton
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.a{fill-rule:evenodd;}techdegree
Aaron Barton
Front End Web Development Techdegree Student 4,999 Points
Posted by Aaron Barton
.a{fill-rule:evenodd;}techdegree
Aaron Barton
Front End Web Development Techdegree Student 4,999 Points

Currently stuck with this task. I'm not sure what I'm doing wrong. Do I just multiplying 1.6 to the font-size?

From what I have gathered it seems I'd have to multiply the 1.6 to the line height which is 2 em but still says its wrong. What am I missing?

index.html 
<!DOCTYPE html>
<html>
  <head>
    <title>Lake Tahoe</title>
    <link rel="stylesheet" href="page.css">
    <link rel="stylesheet" href="style.css">
  </head>
  <body> 
    <header id="top" class="main-header">
      <span class="title">Journey Through the Sierra Nevada Mountains</span>
      <h1>Lake Tahoe, California</h1>
    </header>
    <div class="primary-content t-border">
      <p class="intro">
        Lake Tahoe is one of the most <span>breathtaking attractions</span> located in California. It's home to a number of ski resorts, summer outdoor recreation, and tourist attractions. Snow and skiing are a significant part of the area's reputation.
      </p>
      <a href="#more">Find out more</a>
    </div>
    <footer class="main-footer">
      <p>All rights reserved to the state of <a href="#">California</a>.</p>
      <a href="#top">Back to top &raquo;</a>
    </footer>
  </body>
</html>
style.css 
/* Complete the challenge by writing CSS below */

.intro {
    font-size: 1.25em; 
  line-height: 2.0em;
}

2 Answers

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

The instructions say, "Next, give intro a unitless line-height that's 1.6 times larger than the font-size value."

The word "unitless" is a clue there — you won' t need to use "em" (or any other unit for that matter), just the value.

And the value is a multiplier, so you will be able to supply it as-is.

Barry Snowe
Barry Snowe
51,277 Points
Barry Snowe
Barry Snowe
51,277 Points

Line-height will often be expressed as a percentage, but doesn't have to be. Revisiting this challenge, I had to take a quick guess as to "percentage of what"...but you're looking for an expression like line-height = someNumber