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iOS Swift 2.0 Functions Functions in Swift 2.0 Recap: Functions

Posted by Allison Larson
Allison Larson
3,177 Points

Declare a function named temperatureInFahrenheit. The function should take a single input named temperature of type Doub

Declare a function named temperatureInFahrenheit. The function should take a single input named temperature of type Double and has a return type of Double.

For now, to make the function pass, simply return the value of the temperature parameter from the function. In the next task, we'll add more code to the body.

I keep getting an error of unexpected non void return value

functions.swift 
// Enter your code below

1 Answer

Jason Anders
MOD
Jason Anders
Treehouse Moderator 145,860 Points
Jason Anders
Jason Anders
Treehouse Moderator 145,860 Points

Hey Allison,

Without seeing your code, I'm not able to explain why you are receiving that error.

The challenge wants a function declared with one parameter called "temperature" that will take the type of double. Then you have to declare the return type (using the -> symbol) ... also of type double. Then inside the code block just return the parameter passed into the function.

func temperatureInFahrenheit(temperature: Double) -> Double {
  return temperature
}

I hope that helps. :dizzy:

Wei Wei Shen
Wei Wei Shen
808 Points

Dear Jason Anders, why can't I just : 

func temperatureInFahrenheit(temperature: Double) {
  return temperature
}
Jason Anders
Jason Anders
Treehouse Moderator 145,860 Points
Jason Anders
Jason Anders
Treehouse Moderator 145,860 Points

Hi Wei Wei Shen

I don't have a technical answer for you, so I will give what I believe to be a simple answer. Swift likes to be told what type the function is going to return. Swift is more or less build off of Objective-C, where you always specify type. With that, that's why the instructions for the challenge included what type needed to be returned.

See, you could have the function take in a Double as this one does, but then have it return an Int (after some code inside of the function). So really, Swift just wants to know what to expect.

:dizzy: