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Python Python Basics (2015) Logic in Python Try and Except

Posted by Geet Aneja
Geet Aneja
811 Points

def add(x,y): try: x = float(input("Tell me a number")) y = float(input("Tell me another number"))

What's wrong here?

trial.py 
def add(x,y):
    try: 
        x = float(input("Tell me a number"))
        y = float(input("Tell me another number"))
    except ValueError
    return None
x = float(x)
y = float(y)
else:
    return (x+y)
Ben Slivinn
Ben Slivinn
10,156 Points
Ben Slivinn
Ben Slivinn
10,156 Points

Im sorry, but i can't understand the logic of your code, it will be better if you could explain it, and tell me what the intention of the program. what should the program do?

but until then:

  1. Don't foger ':' in the except.

    except ValueError:

  2. if the 'return None' is a part of 'except' so move it one tab fwd.

    except ValueError:
  return None

  3. The 'else' should be part of "try/except" so you should move it one tab fwd.

  4. i can't see why you use

    x = float(x)
y = float(y)

    again inside the function, if when you ask for user input you used the float function to make sure the input is float type.

1 Answer

Steven Parker
Steven Parker
229,744 Points
Steven Parker
Steven Parker
229,744 Points

You have a few issues here:

  • you don't need any input statements, just work with the supplied arguments
  • check your indentation - everything inside the function must be indented
  • a try, except and else set must all be indented the same amount
  • an except statement requires a colon at the end
  • you won't need to do the float conversions twice, just once inside the try