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C# C# Basics Methods Method Parameters

Define a Multiply function that accepts two parameters

So how am I suppose to do this? I get the right result in the console.

Program.cs
using System;

class Program
{

       static double Multiply(double a, double b){
        return a*b;
       }
    // YOUR CODE HERE: Define a method named Multiply. Remember
    // to use the "static" and "void" keywords: "static void
    // Multiply" (without quotes). Multiply should take two
    // "double" values as parameters.

    static void Main(string[] args)
    {
        Console.WriteLine(Multiply(2, 2.5));
        Console.WriteLine(Multiply(6,7));
        // YOUR CODE HERE:
        // Call Multiply with two arguments: 2.5 and 2.
        // YOUR CODE HERE:
        // Call Multiply with two arguments: 6 and 7.
    }

}

2 Answers

Damien Bactawar
Damien Bactawar
8,549 Points

In the question it instructs you to use the key words "static" and "void". You didn't use "void" and are returning a value as a "double". Void methods do not return anything, they just execute whatever lines are inside them.

Replace "static double Multiply..." with "static void Multiply..." and type "Console.WriteLine(a*b);" instead of "reutrn a*b". Also in "Main" just call the methods like "Multiply(2, 2.5)".

I hope this helps!

Thanks! I miss understood the static void thing and what it means to just "call" and not "return". Thanks for making it clear.