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Yvonne Mutangi
4,618 PointsDefine a string variable named firstName that stores your name. Set the value to your name.
output error
// I have setup a java.io.Console object for you named console
string firstName = "craig";
4 Answers
Felix Sonnenholzer
14,654 PointsHey there,
it is important to have a capital S in String.
String firstName = "craig";
Timothy Hilley
2,292 PointsString, not string. Simple spelling issue. Java is case sensitive
Peter Danglay
861 PointsRemember java is case sensitive so always make sure to have uppercases and lowercases when needed
Yvonne Mutangi
4,618 Pointsstring FirstName ="yvonne";