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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Define a string variable named firstName that stores your name. Set the value to your name.

output error

// I have setup a java.io.Console object for you named console
string firstName = "craig";

4 Answers

Felix Sonnenholzer
Felix Sonnenholzer
14,654 Points

Hey there,

it is important to have a capital S in String.

String firstName = "craig";

String, not string. Simple spelling issue. Java is case sensitive

Remember java is case sensitive so always make sure to have uppercases and lowercases when needed

string FirstName ="yvonne";