Dictionaries

I completed this task with using of tuples. Give you a hint:)

def num_courses(dict):
    for item in dict.items():
#now in item you have a tuple like ('Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'])
#you may get name using index 0 and list of courses using index 1
#item[0] - name, len(item[1]) - number of courses for the teacher

@Andrey Misikhin

Thank you for the hints but it's still not working as I want it.

For example:

def num_courses(dict):
    for item in dict.items():
        dd = len(item[1])
        dd += dd
        print (dd)

num_courses({'mike' : 'maths' , 'scot' : 'english' , 'glen' : ['social' , 'health'] , 'frank' : ['science' , 'trade']})

Two problems I encounter are:

1. len(item[1]) gives the correct number of courses for each teacher if [item] is a list. But if [item] is a string, it gives the number of characters in the string with is not what i want. So using len(item[1]) I get 2 courses each for glen and frank which is correct but I get 4 courses each for mike and scot which is WRONG. That is because len(item[1]) for the string item returns the number of characters in the string and does not count the whole string as one item.

2. Then how do i add up the total number of item[1] for all the items in dict.items(). I thought that dd+=dd should do it but it's not. So calling function as I did above, I should have a total of 6 courses for all the teachers.

Please help to clear this out.

Thank you.

@Andrey Misikhin

Thanks for the last time. For the past three hours i've tried solving another step but cannot get through. This time around it's to know which teacher has the highest number of courses. Some of the courses are listed as before.

```def most_courses(dict): course_count = 0 for teacher, courses in dict.items(): if type(courses) is list: course_count = len(courses) else: course_count += 1 max_count = max(course_count) for teacher in dict.items(): print (teacher, max_count)

most_courses({'Dan' : 'econs' , 'Mike' : 'Phys' , 'Scot' : ['bio', 'stem', 'maths'] , 'Malo' : 'chem' , 'Bigi' : ['trade', 'selling']})

I got this error when i called the function:

Traceback (most recent call last):                                                                                                           
  File "dict_2.py", line 12, in <module>                                                                                                     
    most_courses({'Dan' : 'econs' , 'Mike' : 'Phys' , 'Scot' : ['bio', 'stem', 'maths'] , 'Malo' : 'chem' , 'Bigi' : ['trade', 'selling']})  
  File "dict_2.py", line 8, in most_courses                                                                                                  
    max_count = max(course_count)                                                                                                            
TypeError: 'int' object is not iterable  

Give me some hints and let me try again.

Thank you.

This is what worked for me:

def num_courses(teachers):
    count=0
    for course in teachers.values():
        count += len(course)
    return count

You know the data is in a list so you don't need to check for that (and even if it wasn't, the above mentioned code would just error out because there's no error handling). With that knowledge you can get only the values with dict.values(). This gives you the list of courses stored into the course variable for each loop. You can then count with len() and store that value in your increment counter (count).

I am having a bit of an issue:

The challenge says to return a single list with all the available courses. I have this code which looks to return the correct answer in workspaces but it's failing in the challenge:

def courses(teachers):
    new_list=[]
    for course in teachers.values():
        for c in course:
        new_list.append(c)
    return new_list

returns

['jQuery Basics', 'Node.js Basics', 'Python Basics', 'Python Collections'] 

Any thoughts on what I'm doing wrong?