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Start your free trialMUZ140259 Juliana Kofi
9,532 Pointsdictionary
help am facing challenges
# The dictionary will be something like:
# {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Often, it's a good idea to hold onto a max_count variable.
# Update it when you find a teacher with more classes than
# the current count. Better hold onto the teacher name somewhere
# too!
#
# Your code goes below here.
dicts = [
{'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
'Kenneth Love': ['Python Basics', 'Python Collections']}
]
def most_classes(dicts):
for key in most_classes:
return(most_classes)
1 Answer
Alexander Davison
65,469 PointsTry this code snippet:
def most_classes(teachers):
max_count = 0
teacher_name = ""
for classes, name in zip(teachers.values(), teachers.keys()):
if len(classes) > max_count:
max_count = len(classes)
teacher_name = name
return teacher_name
Also, there is no need to write the "teachers" dictionary. (don't worry; that doesn't mean that you shouldn't)
Hope that helps! ~xela888