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rizwan khan mohammed
1,177 Pointsdictionary
Write a function named members that takes two arguments, a dictionary and a list of keys. Return a count of how many of the items in the list are also keys in the dictionary.
# You can check for dictionary membership using the
# "key in dict" syntax from lists.
### Example
my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
if my_list == my_dict['apples','bananas','coconuts']
return count
members(my_dict, my_list)
3 Answers
wang yang
Courses Plus Student 1,728 Pointsdef members(my_dict, my_list):
counts = 0
for key in my_dict:
counts += my_list.count(key)
return counts
Cindy Lea
Courses Plus Student 6,485 PointsHeres one way you can do it:
def members(d, l): count = 0
for item in l: if d.get(item, None): count = count + 1 return count
rizwan khan mohammed
1,177 PointsHey found it some_dict = {'a': 1, 'b': 2, 'c': 3}
key_list = ['a', 'b', 'd']
def members(some_dict, key_list):
counts = 0
for item in key_list:
if item in some_dict.keys():
counts += 1
return counts