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Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today. # Did it in a weird way but it works lol

str_number3 = str(int(number) / 3) str_number5 = str(int(number) / 5)

if int(str_number3) <= 0 and int(str_number5) <= 0: print(number, " is a FizzBuzz")

elif int(str_number3) <= 0: print(number, " is a Fizz number")

elif int(str_number5) <= 0: print(number, " is a Buzz number")

else: print(number, "is neither a Fizzy or Buzzy number")

Just wanted to see if I could this to work before watching the solution I'm wondering how you tested this to get the impression that it worked — it won't actually work for most numbers.

But some hints about creating a workable strategy:

• it's probably easier to work with numbers than strings
• only one conversion will be needed on the input value
• the "remainder" operator ("%") might be handy The Operator % completely slipped my mind at the time I was doing this lol. I just wanted to try and get something together before watching the solution using only what I've learnt so far.

I do understand that it wont work with most numbers. Thanks for the tips I'll try and get another working version using those.

Regards ```#name = input("Please enter your name: ")
number = int(input("Please enter a number: "))

is_fizz = False
is_buzz = False

if number % 3 == 0 and number % 5 == 0:
is_fizz = True
is_buzz = True

elif number % 3 == 0 and number % 5 >= 1:
is_fizz = True
is_buzz = False

elif number % 3 >= 1 and number % 5 == 0:
is_fizz = False
is_buzz = True

elif number % 3 >= 1 and number % 5 >= 1:
is_fizz = False
is_buzz = False

if is_fizz and is_buzz:
print(number, "is a FizzBuzz")

elif is_fizz and is_buzz != True:
print(number, "is a Fizz")

elif is_fizz != True and is_buzz:
print(number, "is a Buzz")

else:
print(number, " is neither a Fizzy or Buzzy number")
```

I think this works a lot better.

Thanks for the help! Much better! And you can simplify it a good deal from there by just assigning the booleans directly from the comparison. Then you don't need any conditional statements:

```is_fizz = number % 3 == 0
is_buzz = number % 5 == 0
``` ```name = input("Please enter your name: ")
number = int(input("Please enter a number: "))

if(number % 5 == 0):
if(number % 3 == 0):
print("{} is a fizzbuzz number!".format(number))
else:
print("{} is a buzz number!".format(number))
else:
if(number % 3 == 0):
print("{} is a fizz number!".format(number))
else:
print("{} is neither a fizzy or buzzy number.".format(number))
``` Thanks! Saw this in the video later. I further simplified it, I didn't know it was possible for calculations or any functionality to run whilst defining the variable. That makes everything so much more interesting lol. Thanks for the help! :)

Simplified code is as follows:

```#name = input("Please enter your name: ")
number = int(input("Please enter a number: "))

is_fizz = number % 3 == 0
is_buzz = number % 5 == 0

if is_fizz and is_buzz:
print(number, "is a FizzBuzz")

elif is_fizz and is_buzz != True:
print(number, "is a Fizz")

elif is_fizz != True and is_buzz:
print(number, "is a Buzz")

else:
print(number, " is neither a Fizzy or Buzzy number")
```