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Kyle Salisbury
Full Stack JavaScript Techdegree Student 16,363 PointsDid you forget to create the method getTileCount that accepts a char? I feel like I have but it keeps saying I haven't.
public String getTileCount() { int tileCount =0; for(char tile: mHand.toCharArray()) { if (mHand.indexOf(tile)>=0) { tileCount++; } } String cont = Integer.toString(tileCount); return count; }
Maybe i'm just missing the concept or the question but I can't get past this one.
public class ScrabblePlayer {
private String mHand;
public ScrabblePlayer() {
mHand = "";
}
public String getHand() {
return mHand;
}
public void addTile(char tile) {
// Adds the tile to the hand of the player
mHand += tile;
}
public String getTileCount() {
int tileCount = 0;
for (char tile: mHand.toCharArray()) {
if (mHand.indexOf(tile) >=0) {
tileCount++;
}
}
String count = Integer.toString(tileCount);
return count;
}
public boolean hasTile(char tile) {
return mHand.indexOf(tile) > -1;
}
}
2 Answers
Christopher Augg
21,223 PointsHello Kyle, I am not sure if you got this answered yet so I will try and help you out.
The question is asking you to use a for each loop to loop through the mHand Stirng and test each character in that string against a character passed into the method. With characters we can just use the == operator unlike with Strings where we need to use string.equals(string). One way to do this is with the following:
public int getTileCount(char ch) {
int count = 0;
for (char c : mHand.toCharArray()) {
if(c == ch) {
count++;
}
}
return count;
}
Victor Learned
6,976 PointsYour public String getTileCount() is currently not taking ANY variables let alone a char. Thus you aren't actually tell your method what char it should be searching for. Trying something like:
public String getTileCount(char c)
{
int tileCount = 0;
for (char tile: mHand.toCharArray()) {
if (tile == c)) {
tileCount++;
}
}
return tileCount;
}
Kyle Salisbury
Full Stack JavaScript Techdegree Student 16,363 PointsThanks for responding so quick! However with that suggestion i get two errors:
./ScrabblePlayer.java:21: error: char cannot be dereferenced if (tile.equals(c)) { ^ ./ScrabblePlayer.java:26: error: incompatible types: int cannot be converted to String return tileCount; ^ 2 errors
Victor Learned
6,976 PointsYep some reason was thinking a string. Though you could turn it into a Character object and do a .equals compare :)
Kyle Salisbury
Full Stack JavaScript Techdegree Student 16,363 PointsKyle Salisbury
Full Stack JavaScript Techdegree Student 16,363 PointsThanks man, that was it. I don't really understand the c == ch part but i'll keep studying a bit and maybe it will catch on for me. appreciate it!
Christopher Augg
21,223 PointsChristopher Augg
21,223 PointsNo Problem..... The reason for the c == ch is because every character is also a number on the ASCII table. Here is a link to one : http://web.cs.mun.ca/~michael/c/ascii-table.html
In this current program we are specifically making two variables of type char and naming them c and ch. We could name them charOne and charTwo.
These two variables are of type char and hold characters (i.e a b c d e........). These characters are also numbers like I had mentioned (i.e 97 98 99 100 101......). Therefore, if charOne is assigned the character h and charTwo is assigned the character z, then when testing if(charOne == charTwo) will be false because we are essentially testing if 104 is equal to 122.
I hope that helps...