Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

iOS Swift Functions and Optionals Optionals What is an Optional?

Did you use println() one time - ERROR

Not sure what is wrong here. I looked up solutions for this problem and they all match my code unless I looked at them wrong.

search.swift
func search(#name: String) -> String? {
    let names = ["Doc","Grumpy","Happy","Sleepy","Bashful","Sneezy","Dopey"]
    for n in names {
        if n == name {
            return n
        }
    }
    return nil

    if let result = search(name: "Doc"){
      println("Found")

    }

}

1 Answer

The problem is that you are writing the if let statement within the function. All you need to do to correct this is write it after the last curly brace.

func search(#name: String) -> String? {
    let names = ["Doc","Grumpy","Happy","Sleepy","Bashful","Sneezy","Dopey"]
    for n in names {
        if n == name {
            return n
        }
    }
    return nil

}
if let result = search(name: "Doc") {
  println("Found")
  }