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Gurveer Singh
9,004 Pointsdid't understand this question plz
Replace the hard coded values in the output with the name and email values from the contacts array.
<?php
//edit this array
//$contacts[0] will return 'Alena Holligan' in our simple array of names.
$contactone =
array('name' => 'Alena Holligan',
'email' => 'alena.holligan@teamtreehouse.com');
$conatacttwo =
array('name' => 'Dave McFarland',
'email' => 'dave.mcfarland@teamtreehouse.com');
$conatactthree =
array('name' => 'Treasure Porth',
'email' => 'treasure.porth@teamtreehouse.com');
$conatactfour =
array(
'name' => 'Andrew Chalkley',
'email' => 'andrew.chalkley@teamtreehouse.com');
$contacts = array($contactone, $conatacttwo, $conatactthree, $conatactfour);
echo $contacts[0]['name'];
echo $contacts[0]['email'];
echo $contacts[1]['name'];
echo $contacts[1]['email'];
echo $contacts[2]['name'];
echo $contacts[2]['email'];
echo $contacts[3]['name'];
echo $contacts[3]['email'];
1 Answer
Steven Parker
229,732 PointsYou have the right idea, but you want to retain the original HTML markup in the output.
So you might use concatenation to replace the literals with the appropriate variable values. For example:
<?php
/ ...
echo "<li>" . $contacts[0]['name'] . " : " . $contacts[0]['email'] . "</li>\n";