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# disemvowel.py challenge

I am getting a syntax error. Also, do you think this code will solve the challenge?

def disemvowel(word): list(word) while True: if 'a' is in word.lower(): word.remove('a') elif 'e' is in word.lower(): word.remove('e') elif 'i' is in word.lower(): word.remove('i') elif 'o' is in word.lower(): word.remove('o') else 'u' is in word.lower(): word.remove('u') break

```return word
```
disemvowel.py
```def disemvowel(word):
list(word)
while True:
if 'a' is in word.lower():
word.remove('a')
elif 'e' is in word.lower():
word.remove('e')
elif 'i' is in word.lower():
word.remove('i')
elif 'o' is in word.lower():
word.remove('o')
else 'u' is in word.lower():
word.remove('u')
break

return word
```

Here's my solution for the challenge..

```def disemvowel(word):
vowels =  ("a", "e", "i", "o","u", "A", "E", "I", "O", "U")
for vowel in word:
if vowel in vowels:
try:
word = word.replace(vowel, "")
except ValueError:
pass
print(word)
return word

wr=input("enter a word  ")
disemvowel(wr)
```

Hi Salman,

Thank you so much for the solution. Your code is very clean and works well. Thank you for taking the time to help me. Have a great day!

This is an elegant solution. I like it.

You could have written less code by leaving the uppercase letters out of the tuple and just using the ´lower()´ method in the conditional. But still, I like your approach.

There are several problems with your code. First, here is my solution:

```def disemvowel(word):
word = list(word)
for key in word.copy():
if key.lower() == 'a':
word.remove(key)
elif key.lower() == 'e':
word.remove(key)
elif key.lower() == 'i':
word.remove(key)
elif key.lower() == 'o':
word.remove(key)
elif key.lower() == 'u':
word.remove(key)
return word
```

Problem 1: `list(word)` You are calling the `list` method on the argument to the function without assigning the return value to a variable. The `list` method returns an iterable as a list, but it doesn't convert the iterable to a list in place. You have to save it to a variable, which is why you will see in my solution, I use `word = list(word)`.

Problem 2: `is in...` Using "is in" is not valid syntax in Python. You're being a bit too human for the computer. All the computer requires, when you speak to it in Python, is `if x in y: do z`. If you try to use `if x is in y...` it will throw an error.

Problem 3: Not iterating over a copy When you are simultaneously iterating over a list and making changes to that list, like removing elements, you will need to iterate over a `copy()` of that list, but change the list. This is because iterating over a list and also making changes to it at the same time causes strange results, at least to our human brains. Instead, when you are going to iterate over a list and also make changes to it, do it the way I have done it in my example. Use the following format:

```for key in list.copy():
if key == x:
list.remove(x)
```

Notice that I am iterating over a copy of the list, and removing from the original. Remembering this will save you a world of frustration.

Problem 4: Using a while loop When iterating over a list or another iterable, in most cases you will want to use a for loop, not a while loop. While loops are generally used to do the same thing over and over until a certain condition becomes true. But when you are doing something to an iterable data structure like a list, you just want the process to keep on going until it reaches the end of the data structure. In a for loop, you set a variable, and at each iteration of the loop, the variable you set gets assigned to the next item in the list. This allows you to grab ahold of each piece of data in the list and check it for any condition you set and then do something with it. This is harder to accomplish with a while loop. So remember: if you want to keep doing the same process over and over again, use a while loop. But if you want to check a bunch of pieces of data or do something to a bunch of pieces of data, use a for loop.

Good luck!

Wow Michael.

Thank you so much for the excellent reply. You really cleared a lot of questions up that I had. How to I convert the list back to a string? Your code works but the challenge doesn't like it because the answer is printed out as a list instead of a string. I loved how you really broke down all the mistakes with the number topics so it was clear and easy to understand. Thank you Michael!

I think to convert an iterable to a string you just use the `str()` method. I suggest getting into the habit of googling questions and reading documentation. I know documentation is technical and difficult to understand at first but over time it gets easier and it is there to help you. Glad my answer helped!