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Jane Wheatley
926 Pointsdo while #1, #3, #5 ...
I don't understand what I am doing wrong with this question:
var x = 1 do { console.log('#' + _) x += _ ; } while (x <= 15)
where the variables print to 1, 3, 5, 7, 9, 11, 13, 15
I'm filling in the blanks with 2, and 1 respectively, but those are apparently not correct.
1 Answer
Steven Parker
229,744 PointsPerhaps a couple of hints will help:
- the first blank represent where the number values will be taken from (what variable?)
- the second blank represents how far apart the values will be
Alexander B
6,453 PointsAlexander B
6,453 PointsYou want the program to output odd numbers, starting from 1 (the original value of x), and going to 15, so that it resembles this pattern: #1, #3, #5, ... #15. Right off the bat, we can see that it's going up in increments of 2.
In order to do this, you will need the console to output what is currently stored in x. If you do console.log('#' + x) during the first run of the do-while loop, the program will output #1 as a string (remember, x holds the value of 1 currently).
It then goes to the next line, where x will update and increase itself by a new amount; in this case we put 2, so if x was originally 1, then x += 2 results in x assigning itself a new value of 3.
The program then checks for the condition since it wants to stop when x is equal to 15. But since x is equal to 3, and 3 is less than or equal to 15, the condition still holds true, and the program will loop around until x is finally greater than 15.