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Full Stack JavaScript Techdegree Graduate 20,125 PointsDoes these two codes work the same in here?
The code in teacher's notes:
for (let i=0; i<suites.length; i++) {
for (let j=0; j<ranks.length; j++) {
let card = [];
card.push(ranks[j], suites[i]);
deck.push(card);
}
}
My code:
for (let i = 0; i < suites.length; i ++){
for (let j = 0; j < ranks.length; j ++){
let card = [suites[i], ranks[j]];
deck.push(card);
}
}
1 Answer
Steven Parker
231,210 PointsIt looks like you have the item order reversed, but otherwise this would be an improvement on the example by saving a step!
But you can save yet another step and also eliminate the "card" variable completely:
deck.push([ranks[j], suites[i]]);
Swan The Human
Full Stack JavaScript Techdegree Student 19,338 PointsSwan The Human
Full Stack JavaScript Techdegree Student 19,338 PointsThis is exactly how I did it as well haha