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iOS

Don't get a question with logic operators in Swift

What does the following statement evaluate to? (!true || !false) && (true && !false)

I mean I somewhat know what is happening here, but how do you "evaluate" this ? the answers are truth and false. Truth being the correct one, but why is the correct one ?

can somebody explain me in simple terms ? it will be most appreciated.

3 Answers

Alex Hedley
Alex Hedley
16,381 Points

If you take one at a time (!true || !false) && (true && !false)

(false || !false) && (true && !false)

(false || true) && (true && !false)

(true) && (true && !false)

(true) && (true && true)

(true) && (true)

true

For and (&&) both have to be the same For or (||) if one is true then true for not (!) reverse the value

Logical Operators https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Logical_Operators

Operator Usage Description
Logical AND (&&) expr1&& expr2 Returns expr1 if it can be converted to false; otherwise, returns expr2. Thus, when used with Boolean values, && returns true if both operands can be converted to true; otherwise, returns false.
Logical OR ( )
Logical NOT (!) !expr Returns false if its single operand can be converted to true; otherwise, returns true.

Think of the AND logic like a logging into a website, you have a username and a password. If you enter the username AND password correctly, you'll always be able to log into the site because both fields were evaluated to true.

The OR logic just stays either item can be true for the statement to be true.

! just means the opposite of whatever is written... so !true = false (AKA nottrue = false)

THX guys, coding requires a lot knowledge, nevertheless I shall get there eventually.