Don't know how to check if integer is even or odd in Swift 2.0 except by evaluating with remainders.

Question

``` Swift 2.0 ////// Quiz Work //////

// Need to check is each integer is a multiple of 7 or is an even number // then append integer to results array.

var results: [Int] = []

for n in 1...100 { // Enter your code below if n % 7 = 0 || n % 2 = 0 {results.append(n) } results++ } // End code }

// NOT function is suggested to check if n is even. Help?

```logicalOperators.swift
var results: [Int] = []

for n in 1...100 {
    // Enter your code below
    if results
    // End code 
}

Answer 1 · 2016-06-15T19:44:10Z

June 15, 2016 7:44pm

This is what theyre looking for:

var results: [Int] = []

for n in 1...100 { if (n % 7 == 0 && n % 2 != 0) { results.append(n) } }

Answer 2 · 2016-06-15T21:50:04Z

June 15, 2016 9:50pm

Thank you, Cindy! I wa able to figure it out by experimenting a little bit, but the speedy response is appreciated. I was definitely missing a few glaring details.

Answer 3 · 2016-06-16T11:42:21Z

June 16, 2016 11:42am

I'd like to add a little to the discussion just to make the complete answer to your original question.

Don't know how to check if integer is even or odd in Swift 2.0 except by evaluating with remainders.

Divide by 2 and evaluate the resulted remainder is pretty much the standard way of checking for a number's odd/even property in almost any programming language, not just Swift.

There're exceptions of course, for instance, in Ruby programming language, the odd? & even? methods were built-in to the Integer class, in such case, you should just make use of 'em instead of doing the %2 math calculation for the sake of simplicity.

# sample ruby code
2.odd?   #=> false
4.even?  # => true

Ruby can do that, but Swift doesn't have the same utility.

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Will Seith

Will Seith

Don't know how to check if integer is even or odd in Swift 2.0 except by evaluating with remainders.

3 Answers

Cindy Lea

Cindy Lea

Will Seith

Will Seith

William Li

William Li