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john lau
3,471 Pointsdon't really catch the clue
don't really catch the clue
func duplicate<T>(item: T, numberOftimes: Int) -> [T] {
var array = [item]
let item = 1
let numberOftimes = 4
for item in 1...numberOftimes {
array.append(item)
return array as! [T]
}
return [T]()
}
2 Answers
Jhoan Arango
14,575 PointsHello John:
Generics are amazing and one of the best things about swift. They may be hard to understand at first, but once you get the hang of it you'll love them as I do.
You were pretty close in your attempt to pass the challenge, but we can improve your code by doing something a bit more simple. Instead of using a "For in" we can use "while" loop. You did have the idea on using a loop, so that's a good start.
The good thing about the while loop is that you can make it work until it meets a condition. In this case we want to meet the condition of numberOfTimes.
Here is how It would look.
func duplicate<T>(item: T, numbersOfTimes: Int) -> [T] {
// Array of items ( generic items )
var items = [T]()
// Append item till condition is met
while numbersOfTimes != items.count {
items.append(item)
}
// Then we simply return the items
return items
}
If you need more help please let me know..
Also remember to select your best answers to help others know which answers helped you solve and understand your problems.
Good luck
john lau
3,471 Pointsthks Jhoan