Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
Virochaan Ravi
6,940 PointsDon't Understand CHallenge
Please help me understand and see the code involved in this challenge
def loopy(items):
# Code goes here
2 Answers
andren
28,558 PointsThis challenge is actually quite similar to the earlier break challenge. The only difference is that you have to check a specific letter of the item, rather than the item itself. And that you have to use the continue keyword instead of the break keyword.
The continue keyword simply makes the loop skip an item. Pulling out a specific letter in a string can be done in the same way you pull out a specific item in a list by simply using bracket notation.
Here is an example of the solution:
def loopy(items):
for item in items: # Loop though the items list
if item[0] == "a": # Pull out the first letter of the item string (indexes start at 0)
continue # Continue if the first letter is "a"
print(item) # Print the item if that is not the case
If there is something you'd like more details on, or if you are still confused then feel free to ask me follow up questions, I'd be happy to answer anything I can.
Frank Campos
4,175 Points#they are asking you to loop the argument 'items '
#if the first character is 'a' pass, always the first character will at the index 0
#when It find an "a" just pass it
def loopy(items):
for item in items:
if item[0] == 'a':
pass
else:
print(item)