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PHP Build a Basic PHP Website (2018) Adding a Basic Form Objects

Cliff Jackson
Cliff Jackson
2,887 Points

Don't understand how to output $checker?

Either my concatenation is wrong or i am not understanding the question any ideas??

include "class.palprimechecker.php";
$checker = new PalprimeChecker;
$checker->number = 17;

echo "The number " . $checker . ";
echo "(is|is not)";
echo " a palprime.";


2 Answers

9,260 Points

you will need to reference the following to get the number that being set when you are setting $checker->number

echo "The number  " . $checker->number;