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Cliff Jackson2,887 Points
Don't understand how to output $checker?
Either my concatenation is wrong or i am not understanding the question any ideas??
<?php include "class.palprimechecker.php"; $checker = new PalprimeChecker; $checker->number = 17; echo "The number " . $checker . "; echo "(is|is not)"; echo " a palprime."; ?>
you will need to reference the following to get the number that being set when you are setting $checker->number
echo "The number " . $checker->number;