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JavaScript

Posted by Ivan Tomicic
Ivan Tomicic
3,873 Points

Double function or?

Hey guys... I have this script that is looking for ".main-header .container #menu-center" to apply this "active" class when page is scrolled to certain part of content... But I want to target two elements without adding two separate JS files just for that purpose, I tried few things but it always make just one of those two work...

Can you help me out?

$(document).ready(function () {
    $(document).on("scroll", onScroll);

    //smoothscroll
    $('a[href^="#"]').on('click', function (e) {
        e.preventDefault();
        $(document).off("scroll");

        $('a').each(function () {
            $(this).removeClass('active');
        })
        $(this).addClass('active');

        var target = this.hash,
            menu = target;
        $target = $(target);
        $('html, body').stop().animate({
            'scrollTop': $target.offset().top+2
        }, 500, 'swing', function () {
            window.location.hash = target;
            $(document).on("scroll", onScroll);
        });
    });
});

function onScroll(event){
    var scrollPos = $(document).scrollTop();
    $('.main-header .container #menu-center a').each(function () {
        var currLink = $(this);
        var refElement = $(currLink.attr("href"));
        if (refElement.position().top <= scrollPos && refElement.position().top + refElement.height() > scrollPos) {
            $('.main-header .container #menu-center ul li a').removeClass("active");
            currLink.addClass("active");
        }
        else{
            currLink.removeClass("active");
        }
    });
}

2 Answers

Jeff Lemay
Jeff Lemay
14,268 Points
Jeff Lemay
Jeff Lemay
14,268 Points

I believe you want to use find() before you use each() ...

$('.main-header .container #menu-center').find('a').each(function () {
Ivan Tomicic
Ivan Tomicic
3,873 Points

I'm not sure we understood each other...

This script is working fine, but I want it to work on ".otherelement #floatnavigation" as well?

Jeff Lemay
Jeff Lemay
14,268 Points
Jeff Lemay
Jeff Lemay
14,268 Points

Oh, alright. Are you opposed to adding an additional class to your html? You could just do:

$('.toggle-active a').each(function () {
    // actions
}

You'd just add a class of 'toggle-active' to #menu-center and #floatnavigation. I'm not sure how to run the each loop on two different elements (that don't share a class) without duplicating your anonymous function.

Colton Ehrman
PLUS
Colton Ehrman
Courses Plus Student 5,859 Points
Colton Ehrman
Colton Ehrman
Courses Plus Student 5,859 Points

Yeah, I would have to go with Jeff Lemay on this. Just add a unique class to the two elements you want to target.