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JavaScript JavaScript Loops, Arrays and Objects Simplify Repetitive Tasks with Loops Refactor Using a Loop

Evan Hendsbee
Evan Hendsbee
8,081 Points

Easy Loop challenge.

I know this is supposed to be easy but I can't figure out why it isn't looping and logging more than one number. Please help.

script.js
var number = "";

for ( var i = 2; i <= 24; i + 2) {
  number += i;
break
}
console.log(number);
index.html
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

2 Answers

Matthew Long
Matthew Long
28,382 Points

You've almost got it! The first line of your loop is nearly setup correct. The i + 2 part needs to be i += 2 so that i saves its value.

The body of your loop is where you want to log i to the console each time it is looped over. So you don't need the break or the other line inside the body, and move console.log(i) in there. There doesn't need to be anything outside the loop to complete this challenge.

for (var i = 2; i <= 24; i += 2) {
  console.log(i)
}
Evan Hendsbee
Evan Hendsbee
8,081 Points

Thanks so much Matt. I don't know why I didn't think to move the console log into the loop. Appreciate it.