elevatorclosebutton

Question

I'm not sure what I a doing incorrectly and how to fix this. Does anyone know what I'm doing wrong?

function elevatorCloseButton(pushed) {
 var = status;
 if (pushed) {
     var = status;
status = "I'll close when I'm ready.";
    }

}

index.html

<!DOCTYPE html>
<html lang="en">
  <head>
    <title> JavaScript Foundations: Variables</title>
    <style>
      html {
        background: #FAFAFA;
        font-family: sans-serif;
      }
    </style>
  </head>
  <body>
    <h1>JavaScript Foundations</h1>
    <h2>Variables: Hoisting</h2>

    <script>

    function elevatorCloseButton(pushed) {
      var = status;
        if (pushed) {
    var = status;
        status = "I'll close when I'm ready.";
        }

    }

    elevatorCloseButton(true);

    </script>
  </body>
</html>

Answer 1 · 2014-12-07T05:25:00Z

December 7, 2014 5:25am

Lindsey;

A couple of things.

You have var = status;, it should be var status;
You have that declaration twice. Once outside the if statement (Good). Once inside the if statement (not a best practice).

Your code, therefore, needs to look something like:

function elevatorCloseButton(pushed) {
  var status;

  if (pushed) {
    status = "I'll close when I'm ready.";
  }
}

elevatorCloseButton(true);

Does that make any sense?

Happy coding,

Ken

Answer 2 · 2014-12-07T05:24:17Z

December 7, 2014 5:24am

Hi Lindsey,

The problem is that you've declared the variable status twice using the var command. Remove the second declaration and leave the new status value:

function elevatorCloseButton(pushed) {
      var status;
        if (pushed) {
            status = "I'll close when I'm ready."
        }

    }

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Lindsey Davis

Lindsey Davis

elevatorclosebutton

2 Answers

Ken Alger

Ken Alger

Michael De Marre

Michael De Marre