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PHP

Posted by Umair Yaquoob
Umair Yaquoob
7,500 Points

empty results Challenge 3/3

Question "Let's make sure that foreach loop executes correctly if the $flavors array is NOT empty. Add one element to the $flavors array with a value of 'Avocado Chocolate'."

I'm confused don't know what's wrong. here my code below:

<?php

$recommendations = array();

?> <html> <body>

<h1>Flavor Recommendations</h1>
<?php if(!empty('Avocado Chocolate')) { ?>
<ul>
    <?php foreach($recommendations as $flavor) { ?>
        <li><?php echo $flavor;  ?></li>
    <?php } ?>
</ul>
<?php } else { ?>
    <?php echo '<p>There are no flavor recommendations for you.</p>'; ?>
<?php } ?>

</body> </html>

7 Answers

Giovanni CELESTE
Giovanni CELESTE
20,961 Points
Giovanni CELESTE
Giovanni CELESTE
20,961 Points

Hi Umair,

Did you add correctly your flavor in $recommendations?

For what I see from your code, your if is testing the 'Avocado Chocolate', shouldn't it test the $recommendation instead?

For adding a new flavor, write something like this $array[] = $newElement ;. Hope it helps you.

Umair Yaquoob
Umair Yaquoob
7,500 Points
Umair Yaquoob
Umair Yaquoob
7,500 Points

this code below passed on the 2 tasks it just on final one I'm confuse:

<?php if (!empty($recommendations)) { ?> <ul> <?php foreach($recommendations as $flavor) { ?> <li><?php echo $flavor; ?></li> <?php } ?> </ul> <?php } else { ?> <p>There are no flavor recommendations for you.</p> <?php } ?>

Giovanni CELESTE
Giovanni CELESTE
20,961 Points
Giovanni CELESTE
Giovanni CELESTE
20,961 Points

Hi again,

What is your question? Why are you confused?

Umair Yaquoob
Umair Yaquoob
7,500 Points
Umair Yaquoob
Umair Yaquoob
7,500 Points

This is the question i'm not show where I am meant to put the Avacado Chocolate?

"Let's make sure that foreach loop executes correctly if the $flavors array is NOT empty. Add one element to the $flavors array with a value of 'Avocado Chocolate'."

I'm confused don't know what's wrong. here my code below:

<?php

$recommendations = array();

?>

<h1>Flavor Recommendations</h1> <?php if(!empty($recommendations)) { ?> <ul> <?php foreach($recommendations as $flavor) { ?> <li><?php echo $flavor; ?></li> <?php } ?> </ul> <?php } else { ?> <?php echo '<p>There are no flavor recommendations for you.</p>'; ?> <?php } ?>

Giovanni CELESTE
Giovanni CELESTE
20,961 Points

Look again at my previous comment. You have to add your new flavor to the array $recommendations.

Umair Yaquoob
Umair Yaquoob
7,500 Points
Umair Yaquoob
Umair Yaquoob
7,500 Points

That's what I have done but it still wrong here my code below:

<?php

$recommendations = array('Avocado Chocolate');

?><html> <body>

<h1>Flavor Recommendations</h1>
<?php if(!empty($flavors)) { ?>
<ul>
    <?php foreach($recommendations as $flavor) { ?>
        <li><?php echo $flavor;  ?></li>
    <?php } ?>
</ul>
<?php } else { ?>
    <?php echo '<p>There are no flavor recommendations for you.</p>'; ?>
<?php } ?>

</body> </html>

Giovanni CELESTE
Giovanni CELESTE
20,961 Points
Giovanni CELESTE
Giovanni CELESTE
20,961 Points

Okay Umair, let's go back to what you have done.

$recommendations = array('Avocado Chocolate');

You set you array $recommendations and add the flavor 'Avocado Chocolate'. That's good. Then

<?php if(!empty($flavors)) { ?>

Here you make your condition with a $flavors, but where did you get this $flavors? What is it? For Php for now, you only have a $recommendations, no $flavors. That's when your php didn't understand what you meant. Is it ok for you now?

PS: If I remember correctly, it is a good behaviour to code your array like this, and separate HTML from PHP (but that works as well with what you did).

$recommendations = array();
$recommendations[] = 'Avocado Chocolate';

<?php } else { ?>
    <p><?php echo 'There are no flavor recommendations for you.'; ?></p>
<?php } ?>
Umair Yaquoob
Umair Yaquoob
7,500 Points
Umair Yaquoob
Umair Yaquoob
7,500 Points

Thank you for your help I figured it out.