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Anthony Schleich
3,588 PointsEnhancing PhP Challenge
The flavor.php include file contains a function named get_flavor. That function receives no arguments, and it returns a piece of text as its return value. Call that function and assign the return value to a variable named flavor. (If someone could just fix this so I can move on that would be great. I have tried a lot of different things.)
<?php include("flavor.php"); function get_flavor(){
return $flavor; } getflavor(); echo "Randy's favorite flavor of ice cream is ____.";;
?>
4 Answers
Anthony Schleich
3,588 PointsI figured it out:
<?php include("flavor.php");
$flavor = get_flavor();
echo "Randy's favorite flavor of ice cream is ____.";;
?>
Caroline Hagan
12,612 PointsI can see you have a double ;; in your code there...
Travis Roemer
1,847 Points<?php
function get_flavor(){
$flavor = "vanilla";
return $flavor;
}
echo "Randy's favorite flavor of ice cream is " . get_flavor();
?>
Anthony Schleich
3,588 PointsThanks for this. But I figured it out :)