Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community!
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
Anthony Schleich
3,588 PointsEnhancing PhP Challenge
The flavor.php include file contains a function named get_flavor. That function receives no arguments, and it returns a piece of text as its return value. Call that function and assign the return value to a variable named flavor. (If someone could just fix this so I can move on that would be great. I have tried a lot of different things.)
<?php include("flavor.php"); function get_flavor(){
return $flavor; } getflavor(); echo "Randy's favorite flavor of ice cream is ____.";;
?>
4 Answers
Anthony Schleich
3,588 PointsI figured it out:
<?php include("flavor.php");
$flavor = get_flavor();
echo "Randy's favorite flavor of ice cream is ____.";;
?>
Caroline Hagan
12,612 PointsI can see you have a double ;; in your code there...
Travis Roemer
1,847 Points<?php
function get_flavor(){
$flavor = "vanilla";
return $flavor;
}
echo "Randy's favorite flavor of ice cream is " . get_flavor();
?>
Anthony Schleich
3,588 PointsThanks for this. But I figured it out :)